Cutting a string based on the third occcurence of a character

valluvan · #1 (**permalink**) 11-21-2008

Hello,
I am new to unix hence struggling with my requirement.
I have a string like :

ECR/CHQ/GBP/12345.out

I need to get only the ECR/CHQ/GBP portion of the string(cut the string based on the third occurrence of / )...How do it do it?

Many thanks

zaxxon · #2 (**permalink**) 11-21-2008

awk and sed examples:

Code:

echo "ECR/CHQ/GBP/12345.out"| sed 's!^\([^\/]*\/[^\/]*\/[^\/]*\)\/.*!\1!'
ECR/CHQ/GBP

echo "ECR/CHQ/GBP/12345.out"| awk -F/ 'BEGIN{OFS="/"} {print $1,$2,$3}'
ECR/CHQ/GBP

valluvan · #3 (**permalink**) 11-21-2008

Many thanks

Konerak · #4 (**permalink**) 11-21-2008

Or, even easier,

echo "ECR/CHQ/GBP/12345.out" | cut -d'/' -f1,2,3

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