Piping syntax question

johne1 · #1 (**permalink**) 11-20-2008

There are are lots of examples of piping output FROM the 'ls' command TO another command, but how does one pipe output TO the 'ls -l' command?

For example, use 'which' to find a file, then use 'ls -l' to view the permissions, groups, etc. in a single step:

which <filename> | ls -l

returns a long listing of the current directory, not a long listing of the filename and path returned by the 'which' command.

which <filename> | ls -l -

returns a file not found error on '-'

Suggestions, please. Thanks!

John

Ikon · #2 (**permalink**) 11-20-2008

Code:


ls -l `which <filename>`

johne1 · #3 (**permalink**) 11-20-2008

Thanks, Ikon!

jlliagre · #4 (**permalink**) 11-20-2008

Code:

a=$(which filename) && ls -l $a

johne1 · #5 (**permalink**) 11-20-2008

Quote:

Originally Posted by jlliagre

Code:

a=$(which filename) && ls -l $a

Thanks for that alternate solution, jlliagre!

That's better than my idea of doing the same thing with multiple commands on a single commandline with a command separator between them.

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