Print lines between the search pattern

prsshini · #1 (**permalink**) 11-20-2008

hi,
I have a file say x.txt containing

xxx
123
bla
bla
...
you
xxx
dfk
dbf
...
me
xxx
...
...
keeps on..

i need to search for pattern in the line starting xxx in the file. If pattern matched, I need to fetch all the lines till i find next xxx.

Please help.

Konerak · #2 (**permalink**) 11-21-2008

sed -n '/xxx/,/xxx/p' <tst.txt

Will find from the first xxx to the second,
from the third to the fourth,
etc...

prsshini · #3 (**permalink**) 11-21-2008

Awesome.. Works like exactly what i need.. Thanks a lot... Keep rocking!!!

prsshini · #4 (**permalink**) 11-24-2008

Hi, one more help pls... can u let me know to print the same lines but just before the line it finds xxx...

Franklin52 · #5 (**permalink**) 11-24-2008

Assumimg you want the lines before the first xxx:

Code:

awk '/xxx/{exit}{print}' file

Regards

prsshini · #6 (**permalink**) 11-24-2008

Hi
I m sorry for not being clear.. Its like
I want line from XXX till the line before next xxx..
say if
xxx
1
2
3
4
xxx,
i want the lines from first xxx till line4.
Could you please help. Thanks a lot.

Franklin52 · #7 (**permalink**) 11-24-2008

Quote:

Originally Posted by prsshini

Hi
I m sorry for not being clear.. Its like
I want line from XXX till the line before next xxx..
say if
xxx
1
2
3
4
xxx,
i want the lines from first xxx till line4.
Could you please help. Thanks a lot.

Try this:

Code:

awk 'p && /xxx/{exit} /xxx/{p=1}p' file

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