args of 50+ files

lost · #1 (**permalink**) 11-17-2008

Hey..
I've gotten inspired by another thread and used this:
#!/usr/bin/bash
args 2,5 $(<file.list)
It works but I'll like the results separated into different files or back into the 'used'/original files, whatever is easiest.
e.g. use fileA | args 2,5 > fileB or fileA and then do this to 50 files (I thought the idea with the list of files to be handy).
Is there an easy way?
Thanks!

jim mcnamara · #2 (**permalink**) 11-18-2008

Maybe I have not had my coffee yet, but I do not get what you want.
What is args - a script you wrote?

lost · #3 (**permalink**) 11-18-2008

Sorry. Forgot that args is only on our 'server'. Yes, it's a script that 'takes' the stated arguments in the given line/file.
In this case it 'takes' argument 2 and 5 and paste them.
Basicly what I need to do is to 'take' two columns out of a file and repeat that for 50 files.
Please let me know if I still don't make sense..

Thanks!

drl · #4 (**permalink**) 11-18-2008

Hi.

Quote:

Originally Posted by lost

... what I need to do is to 'take' two columns out of a file and repeat that for 50 files ..

The best way to avoid ambiguity and misunderstanding is for you to provide a sample of the data and your expected output.

Please remember to place your posted data in CODE markups -- highlight the data lines with your mouse, then click the # button above the editing window ... cheers, drl

lost · #5 (**permalink**) 11-19-2008

OK.
This is what I have:

Code:

C 306 P  B 85 V 3.46
C 307 K  B 81 H 2.69
C 307 K  B 85 V 3.43
C 309 V  B 82 N 2.67
C 309 V  B 78 Y 3.23
C 309 V  B 81 H 3.42
C 311 Q  B 78 Y 3.46

And this is what I want:

Code:

And even better sorted this way:

Code:

306 85
307 81,85
309 82,78,81
311 78

Then I have to repeat it for 70+ files.
Hope it makes sense now.
Thanks for replying.

rubin · #6 (**permalink**) 11-19-2008

Quote:

Originally Posted by lost

...
And even better sorted this way:

Code:

306 85
307 81,85
309 82,78,81
311 78

Then I have to repeat it for 70+ files.
Hope it makes sense now.
Thanks for replying.

Code:

awk '{printf ($2 in a) ? ","$5 : (NR>1) ? RS $2 FS $5 : $2 FS $5; a[$2]} END{print e}' file

Output:

Code:

306 85
307 81,85
309 82,78,81
311 78

Then you can use a for loop or find+while loop for all of your files.

lost · #7 (**permalink**) 11-20-2008

YOU'RE A STAR!!!!!!!!
THANKS YOU SO MUCH!!!
yippiyeah.... yippiyeah..... ;D
Sorry I didn't get the thing with the for loop for the files, because how do I make the output from each file separated into individual files? Any way I'm so glad it works so even though it's stupid I can manually do the repeats for all the files...

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