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11-14-2008
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Distinct search usisng GREP cmd
Hi All,
I have the following problem where I have been trying but not able to resolve it:- I have a file which has some thousands entries. For eg:- The content of the file is :- ============================================== ./admin.cpp:9:#include "framework/RegistryContext.h" ./admin.cpp:10:#include "framework/LoggingContext.h" ./adminbatchbase.h:10:#include"framework/RegistryInterface.h" ./adminbatchbase.h:11:#include"framework/LoggingInterface.h" ./adminbatchbase.h:12:#include"framework/BatchException.h" =============================================== Now if I count the number of occurences of "framework" then it comes to 5(wc -l) But I want the count to be 2 as there are only 2 distinct files where framework is there. Could somebdy help me with this? Thanks, SD. |
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11-14-2008
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Sorry....The below code will not work as per the requirement
 Try using -w option with grep. If you want the search to be extended in multiple files, try the following command find . 2>/dev/null | xargs grep -w "string" 2>/dev/null Last edited by sriharsha_kvr; 11-14-2008 at 05:27 AM.. Reason: Requirement wrongly understood |
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11-14-2008
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This should work
find . 2>/dev/null | xargs grep -w framework | cut -d ":" -f1 | uniq -d |
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