Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.
|
Hello and Welcome from United States to the UNIX and Linux Forums! Thank You for Visiting and Joining Our Global Community.
|
|
google unix.com
|
|||||||
| Forums | Register | Forum Rules | Links | Albums | FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
| UNIX for Dummies Questions & Answers If you're not sure where to post a UNIX or Linux question, post it here. All UNIX and Linux newbies welcome !! |
More UNIX and Linux Forum Topics You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| Binary operator expected | basisvasis | Shell Programming and Scripting | 4 | 09-26-2008 05:33 PM |
| Error unary operator error | innocent | Shell Programming and Scripting | 2 | 01-30-2008 05:29 PM |
| binary operator expected error | apps_user | Shell Programming and Scripting | 7 | 05-11-2007 08:33 PM |
| arguments expected error | strike | Shell Programming and Scripting | 4 | 05-18-2005 08:18 AM |
| Syntax Error: 'else' is not expected | djschmitt | Shell Programming and Scripting | 6 | 11-12-2002 11:28 AM |
Powered by 
|
|
|
LinkBack | Thread Tools | Search this Thread | Rate Thread | Display Modes |
10-27-2008
|
||||
|
||||
|
unary operator expected error
Hi
I am doing a script like if [ $table_name != "ABC" ] then echo "table name dosent exist" exit fi the problem is if $table_name is null then i am getting the error [: =: unary operator expected Please help me Thanks in advance |
| Bookmarks |
| Thread Tools | Search this Thread |
| Display Modes | Rate This Thread |
|
|
Threaded Mode
