how to grep this

khestoi · #1 (**permalink**) 10-27-2008

in this line
6347 9.0.4 22772 63743 Running C=US,O=SBC,OU=DGBusSvcs,CN=HostLookup

how can i get only this value
63743?

joeyg · #2 (**permalink**) 10-27-2008

Code:

> echo 6347 9.0.4 22772 63743 Running C=US,O=SBC,OU=DGBusSvcs,CN=HostLookup | cut -d" " -f4
63743
> echo 6347 9.0.4 22772 63743 Running C=US,O=SBC,OU=DGBusSvcs,CN=HostLookup | awk '{print $4}'
63743

khestoi · #3 (**permalink**) 10-27-2008

thanks so how do i save it to a variable?
sorry for such a noob question

joeyg · #4 (**permalink**) 10-27-2008

Code:

> myval=$(echo 6347 9.0.4 22772 63743 Running C=US,O=SBC,OU=DGBusSvcs,CN=HostLookup | cut -d" " -f4)
> echo $myval
63743

khestoi · #5 (**permalink**) 10-27-2008

I just got the solution myself by using this ctl_rsrc -l Active | grep 6.1.5 | grep HostLookup | awk '{print $4}' >$VALUE well thanks anyway
another question is if there are many lines then there will be many results for the 4th column
so i need to have some kind of an array for that since i need to access those values to stop all services within those ports
any ideas?

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