How to get a list of files? - Page 3

joeyg · #15 (**permalink**) 10-24-2008

Code:

> ls -w1
./
../
LG_JG_CLIENT_20081024114245_1.txt
LG_JG_CLIENT_200810241142_1.txt
LG_JG_CLIENT_baddata.txt
LG_JG_CUSTOMER_20081024114245.txt
LG_JG_CUSTOMER_20081024114245_1.txt
LM_CM_CUSTOMER_20081024114245_2.txt
LM_CM_TELEPHONE_20081024114245_1.txt
LM_CM_TELEPHONE_20081024114245_2.txt
LM_CM_TELEPHONE_20081024114269_3.txt
LM_JG_CUSTOMER_20081024114245_1.txt

> ls | awk -F"_" 'NF==5 && ($3=="CLIENT" || $3=="CUSTOMER") {print $0}'
LG_JG_CLIENT_20081024114245_1.txt
LG_JG_CLIENT_200810241142_1.txt
LG_JG_CUSTOMER_20081024114245_1.txt
LM_CM_CUSTOMER_20081024114245_2.txt
LM_JG_CUSTOMER_20081024114245_1.txt

> ls | awk -F"_" 'NF==5 && ($3=="CLIENT" || $3=="CUSTOMER") && ($4>20080101000000) {print $0}'
LG_JG_CLIENT_20081024114245_1.txt
LG_JG_CUSTOMER_20081024114245_1.txt
LM_CM_CUSTOMER_20081024114245_2.txt
LM_JG_CUSTOMER_20081024114245_1.txt

Perhaps you can see/understand the logic used here, and expand upon it for your needs.
I make sure five fields -- four _ characters
I see if field 3 is CLIENT or CUSTOMER
I verify that the date > 2080101 (date) 000000 (time)

Leo_NN · #16 (**permalink**) 10-24-2008

Thanks , I've got it:

Quote:

set -o vi
> Version M-11/16/88f

Leo_NN · #17 (**permalink**) 10-24-2008

Thanks joeyg!!!

Leo_NN · #18 (**permalink**) 10-24-2008

HI joeyg,

Quote:

> ls -l | grep "[A-Z]*_[A-Z]*_[A-Z]*_[0-9]\{14\}*_[0-9]*.txt"

What is this in here?: _[0-9]\{14\}*_

joeyg · #19 (**permalink**) 10-24-2008

Quote:

What is this in here?: _[0-9]\{14\}*_

Checking for _ then numerical digits, 14 to be precise.
If 13 or 15, then not selected.

radoulov · #20 (**permalink**) 10-24-2008

Great parallel thread

+ file globbing
+ how to find the version of ksh

Leo_NN · #21 (**permalink**) 10-24-2008

It is Friday, eow, have no more brain energy...

Is there way to use something like IN condition within awk

Quote:

> ls | awk -F"_" 'NF==5 && ($3=="CLIENT" || $3=="CUSTOMER") && ($4>20080101000000) {print $0}'

something like:

Quote:

> ls | awk -F"_" 'NF==5 && ($3 in "$object_list") && ($4>20080101000000) {print $0}'

Thanks and have a great weekend!

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