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cmd sequence to find & cut out a specific string
A developer of mine has this requirement - I couldn't tell her quickly how to do it with UNIX commands or a quick script so she's writing a quick program to do it - but that got my curiousity up and thought I'd ask here for advice.
In a text file, there are some records (about half of them) that have a specific string, say "ABC" followed by a 15 digit number, always at least 2 leading zeros. In rows that have this, it will appear twice, identically. I essentially want to cut out these 18 chars into a file of their own. But, they are not in a fixed column position within the file. Logically, the task is: a) find the rows with ABC00 b) get the position of that first A c) cut starting at that position for 18 characters and write to a new file. example data: ab cdefgABC000000000012345ABC000000000012345sadlfk abcde fgABC000000000012346ABC000000000012346sadlfk abc defgghi jklmn1349d5sadlfk abcdef sldkfdgABC000000000056789ABC000000000056789abcdlkdfj134239d and so on. Desired output ABC00000000012345 ABC00000000012346 ABC00000000056789 Thanks for having a look. Lisa |
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