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Grep for a pattern based on another patter
hi,
I have looked at many grep threads and am unable to find something like this: please help. I have a file which is generated from a report generator and i am trying to load a whole lot of specific data into a table for the users. One field is causing me problems.All the rest i can manage. I want to grep lines with date: (grep "date:" filename).. however i want those dates only where there is a TEST in the 7th line below it and before the next pattern(date ![]() date: 01/01/2001 xx yy zz aa bb cc TEST zz date: 01/02/2001 xx yy zz aa bb cc NOTEST xx date: 01/03/2001 xx yy zz aa bb cc NOTEST yy date: 01/04/2001 xx yy zz aa bb cc TEST aa so the result will be : date: 01/01/2001 date: 01/04/2001 Any help pl... thanks |
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