Variable substitution

Leo_NN · #1 (**permalink**) 10-17-2008

Hi,

That might be pretty simple.
How can I generate a variable name and get their value ?

Thanks a lot.

Something like:

>CUSTOMER_NF=26
> object=CUSTOMER

> echo ${object}_NF
CUSTOMER_NF

> echo ${${object}_NF}
ksh: ${${object}_NF}: 0403-011 The specified substitution is not valid for this command.

> echo $`echo ${object}_NF`
$CUSTOMER_NF

joeyg · #2 (**permalink**) 10-17-2008

Code:

> cust_num=2026
> echo "$cust_num"
2026
>

Leo_NN · #3 (**permalink**) 10-17-2008

Thanks,
but that's not it.

I need dynamically generate and substitute part of the variable name.

object=cust
echo $cust_num

object=policy
echo $policy_num

echo ${$object}_num????
etc...

radoulov · #4 (**permalink**) 10-17-2008

Code:

$ CUSTOMER_NF=26
$ object=CUSTOMER
$ eval echo \$${object}_NF
26

Leo_NN · #5 (**permalink**) 10-17-2008

Quick and easy!

Thanks as always!!!

Leo_NN · #6 (**permalink**) 10-17-2008

hi again,

how should I use correctly:

Quote:

> i_var=26
> eval echo \$${object}_NF
26

> if [[ i_var == `eval echo \$${object}_NF` ]]
> then
> echo OK
> else
> echo "NOT OK"
> fi
NOT OK
> if [[ i_var -eq `eval echo \$${object}_NF` ]]
> then
> echo OK
> else
> echo "NOT OK"
> fi
NOT OK
>

radoulov · #7 (**permalink**) 10-17-2008

Code:

CUSTOMER_NF=26
object=CUSTOMER
eval "tmp=\$${object}_NF"
case $tmp in
  26 ) print OK;;
   * ) print KO;;
esac

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