Hi experts,

I Need to print file names in a certain date range using ls. Please help me with any sample script. Thanks a lot in advance.

Regards,
Satish

If your find command has the capability to find files by age, you can use that. It's a bit tricky if you haven't used it before, but this site is full of examples. Start with the FAQ: http://www.unix.com/answers-frequent...d-command.html

Hi Era,

Thanks for quick reply. But my requirement has changed...i want a command instead of a script which can compare the files and list them with in a given date range. Actually am invoking this command in my service and i will supply two dates as my input and my output shud be a list of files. Please help me.

try

ls -lt

ls -ltr

#!/bin/ksh
#################################################
## File: findDateRange.sh
## Date: May 27, 2008
## Author: Saurav Sen
## Purpose: A script to find the files within
## a given date range
#################################################
echo "You have to provide the path, start date and the end date"
echo
echo "Enter the path to start search"
read fpath
echo "Please enter the start date in the format YYYYMMDD"
read strtdt
echo "please enter the end date in the format YYYYMMDD"
read enddt
touch -t ${strtdt}0000 /tmp/newerstart
touch -t ${enddt}2359 /tmp/newerend
#find ./ \( -newer /tmp/newerstart -a \! -newer /tmp/newerend \) -print
find $fpath \( -newer /tmp/newerstart -a \! -newer /tmp/newerend \) -exec ls -l {} \;