Vi - "The replacement pattern is too long"

hern14 · #1 (**permalink**) 08-20-2008

Hi,

I am trying to replace a value in a script with another value. I am performing a vi command from another script.

Code:

vi - ${conf_path}/CANCEL_CD_PART2.txt<<!
:%s/RANGE/${btch_range}/g
:wq
!

'RANGE' is the current value that the parm in the other script has (PARM1=RANGE), along with some other things. I want to substitute it with the value in $btch_range which is

Quote:

145857150104000,145857160204000,145857170104000,145857180204000,145857190204000,145857220104000,1458 57230104000,1458572401
04000,145857250104000,145857260104000,145857290104000,145857300204000,145857310104000,14585801020400 0,145858020204000,14585805010200
0,145858060104000,145858070204000,145858080104000,145858090204000,145858120104000,145858130104000,14 5858140204000,145858150304000

The values in $btch_range cannot be changed since those are batch numbers generated by the system. When I try to execute the vi command shown above, I get the following error:

Quote:

ex: 0602-075 The replacement pattern is too long. The limit is 256 characters.

Any ideas?

Thanks!

vidyadhar85 · #2 (**permalink**) 08-20-2008

in vi editor you can replace max of 256 bytes..
so try using sed externally it allows upto 4000 chars

hern14 · #3 (**permalink**) 08-22-2008

Thanks! It worked. I used the sed command instead, as you suggested.

Code:

sed "s/RANGE/${btch_range}/g" ${conf_path}/CANCEL_CD_PART2.txt > ${conf_path}/CANCEL_CD.txt

ddreggors · #4 (**permalink**) 08-22-2008

or you could set range to the variable not to the value contained in that variable :

Code:

:%s/RANGE/\${btch_range}/g

notice the "\" before the "$"

so before we have:

Code:

PARM1=RANGE

and after we have:

Code:

PARM1=${btch_range}

as long as this is inside a shell script, if it is in a conf file that will not expand the variable ${btch_range} (replace the variable with it's value when read) then the previous answer is what you want.

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