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07-24-2008
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Text file to a variable
I have a variable which is not being populated with the contents of a text file, and I'm wondering if anyone happens to know how to do this for a sh type script? #!/bin/sh set alertperson = cat /export/home/bdodym/alert.person if [ -f /export/home/bdodym/critabend.tag ] then cat /export/home/bdodym/callout6.msg | rmail $alertperson rm /export/home/bdodym/critabend.tag fi Basically, the alertperson variable is not reading the contents of /alert.person (which is a text file simply containing 1 email address). I appreciate any assistance.... Tim 
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07-24-2008
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I wish it were that easy Ikon!
Amended script: #!/bin/sh alertperson = cat /export/home/bdodym/alert.person echo $alertperson if [ -f /export/home/bdodym/critabend.tag ] then cat /export/home/bdodym/callout6.msg | rmail $alertperson rm /export/home/bdodym/critabend.tag fi Response: 6check2.sh: alertperson: not found Recipient names must be specified
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07-24-2008
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...thankyou, but still its proving tricky this!!
Amended script: #!/bin/sh alertperson=$(cat /export/home/bdodym/alert.person) echo $alertperson if [ -f /export/home/bdodym/critabend.tag ] then cat /export/home/bdodym/callout6.msg | rmail $alertperson rm /export/home/bdodym/critabend.tag fi Response: 6check2.sh: syntax error at line 3: `alertperson=$' unexpected
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07-24-2008
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What is in your file alert.person?
Code:
> cat ~/tmp/alert/alert.person Mickey Mouse > alertperson=$(cat ~/tmp/alert/alert.person) > echo $alertperson Mickey Mouse > echo "$alertperson" Mickey Mouse
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07-24-2008
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worked for me... It put the contents of alert.person in the variable $alertperson.
Code:
# echo "Jim Smith" > alert.person # alertperson=`cat alert.person`; echo $alertperson Jim Smith #
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