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#1
07-18-2008
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List the files without directory path
Hi
I am writing a script to find the list of files in dir1 and my script is place in dir2 while doing ls of files dir1 it is displaying with path. I would like to omit the path and display the only file name so that I can pass it to my script as arguments. for filename in $datafiles/*.dat #cat $filename | do echo "in for loop $filename " grep -i "dummy file" $filename > /dev/null || echo $filename >> temp if [ -s temp ] then touch checkfile fi done This script is taking the path also . Any help Appreciated Thank you Madan 
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#2
07-18-2008
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Something like this?
Code:
echo "./somedir1/somedir2/somefile"| sed 's!.*\/\([^\/]*\).*!\1!g'
somefile
#or
echo "./somedir1/somedir2/somefile"| awk -F"/" '{print $NF}'
somefile
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