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  #1  
Old 05-18-2008
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Join Date: May 2008
Posts: 5
Help with ELIF statement
I am receiving an elif error on line 13 and I can not figure out the reasoning behind it. I have added the then statement that I was initially missing. Any help would be great.


#The purpose of this script is for the end user to be able to enter a positive number
#User enters a number
NUM=$1
#If user enters more than one it will return this statement
if [ $# -ne1 1 ] then
echo "Only enter one number!"
exit
#For if the user enters a negative number
elif [ $NUM -le 0 ] then
echo "Enter a positive number!"
fi
#Executionary if statement
while [ "$NUM" -gt 0 ]
do
printf $NUM
if[ $NUM -gt 1 ] then
printf ","
fi
NUM=$((NUM - 1))
done


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  #2  
Old 05-18-2008
era era is offline
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Join Date: Mar 2008
Location: /there/is/only/bin/sh
Posts: 3,650
You are missing a semicolon before an earlier then. Also -ne is misspelled.

The syntax of the if statement is

Code:
if some command or other; then
   action
else
   otheraction
fi
Because "some command or other" can be as long or short as necessary, you really do need a semicolon or a newline before the "then".
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  #3  
Old 05-18-2008
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Join Date: May 2008
Posts: 5
It still shows me as having an issue with the done portion of my while loop at the end, I tried moving the done above and below the last statement but it wont work.
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  #4  
Old 05-18-2008
era era is offline
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Did you fix the if inside the while also?
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  #5  
Old 05-18-2008
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Join Date: May 2008
Posts: 5
Nope...that fixed it though.

Thanks.
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