If I execute the command "ls -l /export/home/abcde/dev/proj/code/* | awk -F' ' '{print $9}' | cut -d'/' -f6-8" it will list all the files in /export/home/abcde/dev/proj/code/ directory as well as the files in subdirectories also
proj/code/test.sh
proj/code/test1.c
proj/code/unix
proj/code/xml_db


CPP: SUBDIRECTORY
a.out
constr.cpp
fn_ptr.cpp
samp.cpp


MYSCRIPTS: SUBDIRECTORY
autoTest.sh
file2.txt
filenames.txt
filenames.txt


Is there any way to list only the files mentioned in path /export/home/abcde/dev/proj/code/ and should exclude all the files in subdirectories CPP and MYSCRIPTS
proj/code/test.sh
proj/code/test1.c
proj/code/unix
proj/code/xml_db

Thanks in advance...

i) ls -ld
ii) find -maxdepth 1 -type f

Thanks fabtagon
ls -ld worked for me...

Hi i want to list only the files within a directory and not the sub directories if any. i tried ls -ld but that is not working for me.
this is the result if I use it in usr/bin
$ pwd
/usr/bin
$ ls -ld
drwxr-xr-x 4 bin bin 40960 Mar 17 2008 .
$

What shell you are using (exact version, if possible)?

I am using K shell but how do I know the version??

$ echo $0
-ksh

OK,
you may try:

It will return the release of the mksh and pdksh (if I recall correctly).

Otherwise you may try:

and it works with ksh93 (that's the most powerful implementation).

If none of the above works, you probably have ksh88 (^V to display its version).

Anyway, I suppose fpmurphy will offer a more succinct solution with ksh93, meanwhile you may try: