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05-13-2008
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Command not working
Hi,
I am running a command this way grep -l ` cat get_list_data.lst | awk '{ print $2 }' ` /wss/test/trans/*CASE* What I am trying to do is, get the second field from the file get_list_data.lst and then grep it in the path /wss/test/trans/ But it says grep: can't open 00000000990001399144 grep: can't open 00000000990001399113 These numbers are the second filed outputs. Please help. Thanks and Regrds, Gideon 
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05-13-2008
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Code:
awk '{ print $2 }' get_list_data.lst > ./data.sed
grep -l -f ./data.sed /wss/test/trans/*CASE*
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05-14-2008
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Hi,
Thanks for the reply. But I could like to know the snag in the given command. Or the reason why it is not working. Thanks and Regards, Gideon.
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05-14-2008
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You need to use proper quoting.
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