Command not working - UNIX for Dummies Questions & Answers

preethgideon · #1 (**permalink**) 05-13-2008

Hi,
I am running a command this way

grep -l ` cat get_list_data.lst | awk '{ print $2 }' ` /wss/test/trans/*CASE*

What I am trying to do is, get the second field from the file get_list_data.lst and then grep it in the path /wss/test/trans/
But it says

grep: can't open 00000000990001399144
grep: can't open 00000000990001399113

These numbers are the second filed outputs.

Please help.

Thanks and Regrds,
Gideon

jim mcnamara · #2 (**permalink**) 05-13-2008

Code:

awk '{ print $2 }' get_list_data.lst > ./data.sed
grep -l -f ./data.sed   /wss/test/trans/*CASE*

preethgideon · #3 (**permalink**) 05-14-2008

Hi,
Thanks for the reply. But I could like to know the snag in the given command. Or the reason why it is not working.

Thanks and Regards,
Gideon.

era · #4 (**permalink**) 05-14-2008

You need to use proper quoting.

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