Try this one:

Regards

> uname -a
SunOS e2dsavcshrdev01 5.8 Generic_117350-52 sun4u sparc SUNW,Sun-Fire-880

SunOS release 5
How do I find sed and awk versions

See if using /usr/xpg4/bin/awk works better than /usr/bin/awk or /bin/awk

hi Franklin,

awk -v path="/export/home/vinay/" -F "|" '$1 == "AAA" {print $0 > path $1}' number.dat

gives an error:
awk: syntax error near line 1
awk: bailing out near line 1

Please help me if possible


Era I could not get your comment #24.

Regards,
Vinay

You don't have /usr/xpg4/bin/awk on your system, or you didn't understand how to try it? Use the full path name instad of just "awk"; or try "nawk" instead of "awk" (if I understand correctly, that's identical to XPG4 awk, on the Sun box I have access to at least).

Use nawk or /usr/xpg4/bin/awk on Solaris.

Regards

Hi Franklin, Era Shiva, Unix gurus,

I finally got the answer. The script you suggested works. It goes like this:
/usr/xpg4/bin/awk -F '|' '$1 == "AAA" { print >"/export/home/vinay/AAA.dat";} $1 == "BBB" { print > "/export/home/vinay/BBB.dat";}' number.dat

Truly good. Thanks a lot for your support . Now I am able to use it in my project.

But one small doubt with respect to comment #13.. I am not able to give my desired path..
sed -e '/^AAA /w/export/home/cmohanku/vinay/AAA1.dat' -e '/^BBB /w/export/home/cmohanku/vinay/BBB1.dat' a.dat
isnt woking. Kindly assist if possible.

Another round of thanks to Franklin, Era, Shiva

Regards,

Vinay