command line args 2

skooly5 · #1 (**permalink**) 04-06-2008

I have this while loop and at the end I am trying to get it to tell me the last argument I entered. And with it like this all I get is the sentence with no value for $1. Now I tried moving done after the sentence and it printed the value of $1 after every number. I don't want that I just want the last argument entered.

while [ $# -gt 0 ]
do
echo "$#"
shift
sleep 1s
done

echo The last command line argument you entered is $1.

can anyone help?

fpmurphy · #2 (**permalink**) 04-06-2008

Try the following ...

Code:

while [ $# -gt 1 ]
do
    echo "$#"
    shift
    sleep 1s
done

echo The last command line argument you entered is $1.

skooly5 · #3 (**permalink**) 04-06-2008

that worked except now when it counts down it stops at 2.
5
4
3
2

The last command line you entered is $1.

Can I get the 1 back? So it reads

5
4
3
2
1

The last command line you entered is $!.

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