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[bash]Stripping lines from a list

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#1 (permalink)

03-28-2008

noratx

Registered User

Join Date: Mar 2008

Posts: 30

[bash]Stripping lines from a list

Hello!

I have a script that is (among other things) doing the following:

Code:

list=/tmp/list1.txt
ncftpls -u <user> -p <password> -x "-l1" server.domain.tld > $list
cat $list | nl
echo "Choose file: "
read file
cat /tmp/list1.txt | nl | grep $file | sed -e "s/$file//g" -e "s/ //g" | column -t > /tmp/list2.txt
cat /tmp/list2.txt

With this, i want to choose a file that is located on a server and download it.
the sed lines was given to me on a guy on another forum who said it should do the trick. And it did, somewhat.
In the directory, i have around 40 files.
if i choose 1 - 9, it gives me a list with several lines like this

Code:

Choose file:
9
2 full_mysql_dump_2008-03-24_0:00.sql.gz full_mysql_dump_2008-03-25_06:00.sql.gz 10 full_mysql_dump_2008-03-25_0:00.sql.gz 18 full_mysql_dump_2008-03-26_0:00.sql.gz 1 full_mysql_dump_2008-03-26_12:00.sql.gz 2 full_mysql_dump_2008-03-28_06:00.sql.gz 30 full_mysql_dump_2008-03-28_0:00.sql.gz 35 full_mysql_dump_2008-03-2_00:00.sql.gz 3

but if i choose a higher number, it gives me this:

Code:

Choose file:
33
full_mysql_dump_2008-03-28_18:00.sql.gz

Just as i want it to do.

In this other script that i am working on, i am using the exact same thing, but this time with another directory on the same remote server, where it is only 2 files. (there will be more files there later).
The result is like the first example.
It doesn't cut away all the other lines that i don't want to have there.

Any of you guys who may know what is wrong, or maybe another solution for my problem?

Last edited by noratx; 03-28-2008 at 09:58 PM.. Reason: correcting typos

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