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03-24-2008
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Shell script $0 argument
Hi,
If not running a shell script file in current shell (. ./fileName) then $0 represents the executable file name. But in case of invoking shell script file in current shell then i m getting "$0 as -bash" . In such case how can i get the program name (running shell script file name)? Thanks, |
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03-24-2008
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Sorry, you can't :/
As far as I know, it's a shell builtin so it won't even be present on the process table. |
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03-25-2008
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Right, you can't. The thing is, you're not executing the script when you call it like "bash scriptname." You're executing bash, and bash is using that file as input.
This is why you can still run "bash scriptname" when the file doesn't have execute permissions set. ShawnMilo |
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