ls command output to variable in script

dsrookie · #1 (**permalink**) 03-10-2008

Hi,

I wrote a script to get the oldest file from a directory path (which is passed as a parameter to the script)

#########################################################

XMLFILE_PATH={$1}

cd $XMLFILE_PATH

JPM_FILENAME = `(ls -tr User* | head -1)`

#echo $JPM_FILENAME

###### END

What is the correct syntax for getting the filename (starting with "User") into JPM_FILENAME from the ls command.

Also while calling the script does the path needs to be in quotes?

Thanks

Franklin52 · #2 (**permalink**) 03-10-2008

Try:

Code:

JPM_FILENAME=$(ls -tr User* | head -1)

or

Code:

JPM_FILENAME=`ls -tr User* | head -1`

without spaces around the "=" sign.

Regards

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