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  #1 (permalink)  
Old 02-23-2008
meili100 meili100 is offline
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Join Date: Mar 2007
Posts: 33
What's wrong with this line: if ${TEST:?} ; then echo empty; fi

I want to print "empty" if $TEST is empty.

TEST=
if ${TEST:?} ; then echo empty; fi

But it doesn't work. What's wrong?
  #2 (permalink)  
Old 02-23-2008
zazzybob's Avatar
zazzybob zazzybob is offline Forum Advisor  
Registered Geek
  
 

Join Date: Dec 2003
Location: Melbourne, Australia
Posts: 2,100
Code:
$ cat > foo.ksh
#!/bin/ksh
TEST=
FOO=${TEST:?empty}
$ chmod +x ./foo.ksh$ ./foo.ksh
./foo.ksh: line 3: TEST: empty
$ sed 's/^TEST=/TEST=something/' foo.ksh > foo2.ksh
$ chmod +x ./foo2.ksh
$ ./foo2.ksh
$
No need for the conditional structure, a simple variable assignment will do it.

Cheers,
ZB
  #3 (permalink)  
Old 02-23-2008
fpmurphy's Avatar
fpmurphy fpmurphy is offline Forum Staff  
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Join Date: Dec 2003
Location: Florida
Posts: 1,927
${TEST:?} will cause your script to exit immediately. If you want to exit more
gracefully or do some cleanup, the following method of testing for an null or
empty string may be more useful.

Code:
#!/usr/bin/ksh

TEST=

if [[ ! $TEST ]]
then
   echo "empty"
fi
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