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01-31-2008
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grep required pattern and next 2 or 3 lines
dear ones
pl.kindly help me 1) how to print(grep) required pattern and following 2 or 3 lines. 2) grep required pattern(to print)+above 2 lines+below 2 or 3 lines.from a report file. ex: we have some report file kf askfjsk fksaj fk skf sjfksjd kff sjfkjs kf jskdjfklsd jfklsdf sdkfjsd fsd jkfsdja fkjsdklf jsdklfj klsdj fklsd jkfjsdkfj ksd jfksdjf 456015 jf sakjlf ksld flksdjklfj sakl jfklsdajklfj sdalfjsdj fksldjfls djfkl i want to print 456015 and next 1 or 2 lines in some cases. and 456015 + above one line +below 1 or 2 lines. |
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02-01-2008
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print 456015 and next one line:
Code:
sed -n '/456015/ {p; n; p;}' file
Code:
sed -n '/456015/ {p; n; p; n; p;}' file
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02-01-2008
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this also
can u say how to print the line above that search string?
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02-01-2008
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Priting the lines before pattern
The forum has the answer,please check
Pattern matching in file and then display 10 lines above every time Thanks Nagarajan G |
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