Create Year directory, date subdirectory and archive the file

madhunk · #1 (**permalink**) 12-12-2007

Hi,

After checking all the UNIX threads, I am able to come up with a solution so far. I am working on a shell script where it moves the files to a certain directory. The conditions to check are

1) Check if the file exists in the current directory.
2) Check if the destination directory exists.
3) If the destination directory exists, then create a Year sub directory under it. If the Year sub directory already exists, then skip to the next step.
4) If the Year sub directory exists, then check if the Date sub directory exists. If it exists, move the file else create the sub directory and move it.

I did work on the script and it is erroring out. I was wondering if this is the right way to do it or is there is a better way to do it.

Please advice...

Code:

#Check Number of Parms

if [ $# -eq 3 ]
then
  echo ""
  echo "Start of $0"
  echo ""
else
  echo "Usage: $0 <INPUT DIRECTORY> <DEST DIRECTORY> <FILE NAME> "
  exit 1
fi

#|-----------------------------------------------------------------------------|
#| Initialize Variables
#|-----------------------------------------------------------------------------|

INPUTDIR=$1
DESTDIR=$2
FILENAME=$3

FILE_SUFFIX=`date '+%Y-%m-%d-%H.%M.%S.000000'`
YEAR_DIR=${DESTDIR}/`date +%Y`
DATE_DIR=${YEAR_DIR}/`date +%Y%m%d`

#|-----------------------------------------------------------------------------|
#| Check for existence of the file name in the specified directory
#|-----------------------------------------------------------------------------|

cd ${INPUTDIR}

if [ ! -s "${FILENAME}" ]
then
    echo "\tError: File $FILENAME Found, Archiving!"
else
    echo "\tError: File $FILENAME Not Found, Aborting!"
    exit 1
fi

#|-----------------------------------------------------------------------------|
#| Check for existence of the Year directory in the specified destination 
#| directory. If it doesn't exist, then create it. Example: 2007
#|-----------------------------------------------------------------------------|

cd ${DESTDIR}

if [ ! -d "${YEAR_DIR}" ] || [ ! -w "${YEAR_DIR}" ]
then
    echo "\nERROR: ${YEAR_DIR} is not a directory..Making ${YEAR_DIR} one!"
    mkdir ${DIR}/${YEAR_DIR}
else
    echo "\nERROR: Cannot create a directory"
    exit 1
fi

#|-----------------------------------------------------------------------------|
#| Check for existence of the Date directory in the Year directory under 
#| destination directory. If it doesn't exist, then create it. Example: 20071210
#|-----------------------------------------------------------------------------|

cd ${YEAR_DIR}

if [ ! -d "${DATE_DIR}" ] || [ ! -w "${DATE_DIR}" ]
then
	mkdir ${YEAR_DIR}/${DATE_DIR}
	mv ${FILENAME} ${FILENAME}.$FILE_SUFFIX "${DATE_DIR}"    
	echo "\tRenamed and appended the suffix ${FILE_SUFFIX}"     
else    
    echo "\nERROR: ${DATE_DIR} is not a directory or is not writable"
    exit 1
fi

echo ""
echo "End of $0"

Lakris · #2 (**permalink**) 12-12-2007

Well, there are a few things in Your script that I find a bit strange. Do You want to call this script for each file You want to process? Why do You want nanoseconds if they are always static? Don't You just want to check for existence of a file? And there are a few other syntax errors as well (for example DIR is not defined) and some things will work with absolute paths but not relative.

Anyway, strip off some stuff (to make it shorter) and get to the essence of if, try the following. Unless it is important to know if a directory exist or not, just create it when You need it. An example:

Code:

if [ ! $# -eq 3 ]
then
  echo "Usage: $0 <INPUT DIRECTORY> <DEST DIRECTORY> <FILE NAME> "
  exit 1
fi

FILE_SUFFIX=`date '+%Y-%m-%d-%H.%M.%S.000000'`
FINAL_DEST_DIR=$2/`date +%Y`/`date +%Y%m%d`

if [ -f "$1/$3" ] 
then
    echo "File $3 Found in $1, moving it to $FINAL_DEST_DIR/$3.$FILE_SUFFIX"
    mkdir -p $FINAL_DEST_DIR
    mv $1/$3 $FINAL_DEST_DIR/$3.$FILE_SUFFIX
else
    echo "\tError: File $3 Not Found"
fi

Maybe it can help You a bit on the way.

madhunk · #3 (**permalink**) 12-13-2007

Thank you very much Lakris...The code looks much simpler and better..I am always learning better ways to do it.

Thanks again...

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