Count number of occurences of a word - Page 2

$antaclau$ · #8 (**permalink**) 11-30-2007

Hi,

I am not much of an expert. But maybe we could something primitive like the following:

#!/bin/sh
#
# Usage: kountword "200" filename
#
srchWord="$1"
srchFilename="$2"

ctr=0
while read strLine
do
for eachWord in `echo $strLine`
do
if [ "$eachWord" = "$srchWord" ]
then
ctr=`expr $ctr + 1`
fi
done
done < srchFilename
printf "\n\ntheFile contains %s : %d times\n\n" $srchWord $ctr

#-----

I've not tried it but I beleive this should work

Thanks
$anta

roussine · #9 (**permalink**) 06-25-2009

Quote:

Originally Posted by Yogesh Sawant

using Perl: run this script as :

Code:

$ perl search_word.pl 200 filename

Cheers everyone!
I have a particularly similar need to count occurrences of words. The detail is that the words are many and are contained in ahother file.

Perl experts, can u pls tell if it's possible to modify this script such that it accepts a file with strings to count in another file?

and example string file would be:

roweiurwoiur
gfdkgjdlfkgjh
wiruyweoiry

i.e. one string per line.

The file to search in contains these strings delimited by non-word-constituent characters, not blanks.

thank u much in advance!

PS I tried this script with my data - it works! although finding strings one by one seems not feasible..

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