Positional parameters - UNIX for Dummies Questions & Answers

shalu@ibm · #1 (**permalink**) 11-22-2007

I need to get file names from commandline arguments, it may be any no of arguements, Using for loop i got but how do i display it, bcoz $i will give the number i is assigned $$i is not working either $($i), i need the names of the files got in the arguement

ranj@chn · #2 (**permalink**) 11-22-2007

Code:

#!/bin/ksh
while (($1))
do
echo $1
shift
done

For your 'for' loop issue try

Code:

eval echo \$$i

porter · #3 (**permalink**) 11-22-2007

or alternatively

Code:

#!/bin/sh

for d in $@
do
    echo $d
done

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