command to get count in unzipped folder

arunkumar_mca · #1 (**permalink**) 10-17-2007

Hi All,

Is there is a way to do this in a single unix command

I have unzipped some files into a directory ..

I want to check the count of the files in the directory and also i need to check whether the files is having read permision or not.. I know it can be done by a script isthere any way to it in a single command

Thanks,
Arun

tomas · #2 (**permalink**) 10-17-2007

you can use a semicolon ";" to separate commands. this allows you to run multiple commands in a single string. remember if you need the output of one command to be the input of another to use a pipe "|".

$ uncompress file; wc -l path/file; etc

arunkumar_mca · #3 (**permalink**) 10-17-2007

Thanks thomas ..

But i want to list the files only which has read permision

Thanks,
Arun

porter · #4 (**permalink**) 10-17-2007

Code:

man test

...

    -r file       True if file exists and is readable.

matrixmadhan · #5 (**permalink**) 10-17-2007

Quote:

Originally Posted by arunkumar_mca

Thanks thomas ..

But i want to list the files only which has read permision

Thanks,
Arun

Code:

ls -l | awk '{ if( substr($0, 2, 1) == "r" ) { print } }'

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