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10-07-2007
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awk field not recognized in backquotes
Hi,
I am writing a script to use awk to generate a set of cp commands from an input file abc. file abc: /data/a.dbf /data/june/b.dbf desired output: cp -pr a.dbf /data/a.dbf cp -pr b.dbf /data/june/b.dbf script: $ cat abc | awk '{ print "cp -pr '`basename $1`' " $1 }' I tried to use awk with basename command, but it seems that the field $1 in backquotes is not recognized by awk. How to fix it? Many thanks, voa2mp3 
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10-07-2007
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A few solutions
awk: Code:
$ awk '{s=$0;gsub( /^.*\//, "" );printf("cp -pr %s %s\n", $0, s )}' abc
cp -pr a.dbf /data/a.dbf
cp -pr b.dbf /data/june/b.dbf
Code:
$ sed 's!^\(.*\)/\(.*\)!cp -pr \2 \1/\2!' abc cp -pr a.dbf /data/a.dbf cp -pr b.dbf /data/june/b.dbf Code:
$ while read file; do echo "cp -pr ${file##*/} ${file}"; done < abc
cp -pr a.dbf /data/a.dbf
cp -pr b.dbf /data/june/b.dbf
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10-07-2007
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Hi.
Quote:
Code:
#!/usr/bin/env sh
# @(#) a1 Demonstrate awk feature "command | getline".
set -o nounset
echo
## Use local command version for the commands in this demonstration.
echo "(Versions of codes used in this script -- local code \"version\")"
version bash awk
echo
awk '
{ command = "basename " $1
command | getline file
print "cp -pr " file " " $1 }
' data1
exit 0
Code:
% ./a1 (Versions of codes used in this script -- local code "version") GNU bash, version 2.05b.0(1)-release (i386-pc-linux-gnu) GNU Awk 3.1.4 cp -pr a.dbf /data/a.dbf cp -pr b.dbf /data/june/b.dbf
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10-07-2007
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Some other ways
 Code:
% set -- $(<file)
% paste -d" " <(printf "cp -pr %s\n" "${@##*/}") <(printf "%s\n" "$@")
cp -pr a.dbf /data/a.dbf
cp -pr b.dbf /data/june/b.dbf
Code:
zsh 4.3.4% <file while IFS= read;do print -r "cp -pr $REPLY:t $REPLY";done cp -pr a.dbf /data/a.dbf cp -pr b.dbf /data/june/b.dbf Code:
zsh 4.3.4% awk '$0="cp -pr "$NF" "$0' FS="/" file cp -pr a.dbf /data/a.dbf cp -pr b.dbf /data/june/b.dbf
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