|
|
|
|
|||||||
| UNIX for Dummies Questions & Answers If you're not sure where to post a UNIX or Linux question, post it here. All UNIX and Linux newbies welcome !! |
More UNIX and Linux Forum Topics You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| SED replace string by occurrence | uttamhoode | Shell Programming and Scripting | 4 | 03-05-2008 01:04 AM |
| Getting the lines between last occurrence of two patterns | rvz | Shell Programming and Scripting | 7 | 02-14-2008 03:37 AM |
| Finding nth occurrence in line and replacing it | stresing | UNIX for Dummies Questions & Answers | 5 | 02-01-2008 12:56 AM |
| Replace second occurrence only | lyoncc | Shell Programming and Scripting | 5 | 12-26-2007 07:21 PM |
| Grep for the same occurrence or maybe Sed | hcclnoodles | Shell Programming and Scripting | 4 | 09-11-2002 09:25 PM |
 |
|
|
Submit Tools | LinkBack | Thread Tools | Display Modes |
10-04-2007
|
|||
|
|||
|
awk + last occurrence
Hi,
I'm attempting to search, using awk, a pattern range in a file. Something like: >awk '/first bit of text.../,/...last bit of text/' file Is it possible to print only the last (or first) occurrence of the pattern range this way? Thanks for any suggestions. Al 
|
| Forum Sponsor | ||
|
|
|
10-04-2007
|
||||
|
||||
|
from the top of my head - not easly and/or awk-natively, but:
Code:
/123/ {a=""}
# last
#/123/,/456/ {a=(a=="") ? $0 : a RS $0}
# first
/123/,/456/ {a=(a=="") ? $0 : a RS $0}
/456/ {exit}
END {
print a
}
|
Linear Mode
