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09-28-2007
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How to List and copy the files containing a string
 I have more than 8000 files in a dir, I need to copy to other dir which containing the "sample" I tried grep -il "1189609240791-1268115603299237276@216.109.111.119 ' | cp /tmp/inv Nothing is happening for long time for 100 file dir too, Any one can help me? |
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09-28-2007
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For filenames with no embedded spaces(or other pathological characters):
Code:
mv $(grep -l '1189609240791-1268115603299237276@216.109.111.119') /tmp/inv Aah, and if you get "too many arguments", use zsh/zargs  Last edited by radoulov; 09-28-2007 at 10:26 AM.. |
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09-28-2007
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Quote:
 ctlrws001[/tmp/inv1]$ cp $(grep -l "1190151616066-4284832706333417688@216.109.111.119') /tmp/inv/test > ctlrws001[/tmp/inv1]$ grep -l "1190151616066-4284832706333417688@216.109.111.119 > |
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09-28-2007
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Quote:
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09-28-2007
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Just curious, I tried this:
Code:
zsh 4.3.4% for i ({1..400000}) touch "$i".txt
Code:
zsh 4.3.4% rm *txt zsh: argument list too long: rm zsh 4.3.4% autoload zargs zsh 4.3.4% zargs *txt rm -- zargs:168: subscript too big: 397905 zsh 4.3.4% while :;do rm *.txt([1,20000]);done zsh: argument list too long: rm Code:
while :;do rm *.txt([1,10000]);done |
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