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08-30-2007
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scipt dividing strings /reg expr
Hello! I've got txt-file containing lots of data in sentences like this: Code:
;;BA;00:00:03:00;COM;CLOQUET-LAFOLLYE;SIMON; but sometime more than on in a line like this: Code:
;;BA;00:00:03:00;COM;CLOQUET-LAFOLLYE;SIMON;;;BA;00:00:03:00;REA;RTL9;;;;BAC;:00;TIT;SEMAINE SPECIALE ~SSLOGAN~T DVD;; Now I would like to cut this down that I have only one sentence per row: Code:
;;BA;00:00:03:00;COM;CLOQUET-LAFOLLYE;SIMON; ;;BA;00:00:03:00;REA;RTL9;; ;;BAC;:00;TIT;SEMAINE SPECIALE ~SSLOGAN~T DVD;; (So I need a break after every 7th ";"). I tried Code:
echo `awk '{gsub("[;][.]\{0;}[;][.]\{0;}[;][.]\{0;}[;][.]\{0;}[;][.]\{0;}[;][.]\{0;}","[;][.]\{0;}[;][.]\{0;}[;][.]\{0;}[;][.]\{0;}[;][.]\{0;}[;][.]\{0;}\012");print $0}' $fileName0 > $fileName1`
but this is obviously completly wrong...  Does anybody have an good idea how I could get the results I want?!? Thanks very much for any kind of help! |
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08-30-2007
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Thanks for that, it's working very well. But now I've got another, very similar problem... I've got the same data: Code:
FP7F111;;BAC;00:00:30:00;TIT;SEMAINE SPECIALE “BANDE DE SAUVAGES”;; ;;BA;00:00:03:00;COM;CLOQUET-LAFOLLYE;SIMON; ;;BA;00:00:03:00;REA;RTL9;; ;;BAC;:00;TIT;SEMAINE SPECIALE “BANDE DE SAUVAGES”;; but now I have to remove all the linebreake (ASCII 12) so that it looks like this: Code:
FP7F111;;BAC;00:00:30:00;TIT;SEMAINE SPECIALE “BANDE DE SAUVAGES”;;;;BA;00:00:03:00;COM;CLOQUET-LAFOLLYE;SIMON;;;BA;00:00:03:00;REA;RTL9;;;;BAC;:00;TIT;SEMAINE SPECIALE “BANDE DE SAUVAGES”;; And I have this time absolutly no idea how to do this... Sorry for my stupid qustions, I think I have to get some experience with reg expr's very quickly... |
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08-30-2007
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Code:
awk '$1=$1' RS= file Use nawk or /usr/xpg4/bin/awk on Solaris. Or, of course, with tr: Code:
tr -d '\12'<file Code:
tr -d '\n'<file Last edited by radoulov; 08-30-2007 at 10:48 AM.. Reason: addition |
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