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08-08-2007
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Extract the Pattern
Hello All,
can anyone help me out in extracting the pattern from a file... The Input file is: NFS B.11.11 ONC/NFS; Network-FileSystem,InformationServices,Utilities|123 NParProvider B.11.11.01.04.01.01 nPartition Provider|456 NPartition A.01.02 Enhanced NPartition Commands/789 Networking B.11.11 HP-UX_Lanlink_Product|1111 NisLdapServer B.04.00.02 The NIS/LDAP Gateway (ypldapd)|2222 I need to extract the pattern ypldapd from the fifth line which is enclosed between the brackets.. I need a script in ksh Thanks in Advance |
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08-08-2007
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The first part of the sed statement is to extract the line containing the pattern, So 1,4d or '/NisLdapServer/!d will delete all the lines except for the 5th line and then the second part i am extracting the pattern inbetween the braces
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08-08-2007
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Code:
awk '/NisLdapServer/ { print substr( $0, index($0, "(") + 1, index($0, ")") - ( index($0, "(") +1 ) ) }' filename
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08-08-2007
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Code:
awk '/NisLdapServer/{
n=split($NF,r ,"|")
print r[1]
}' file
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