Hi,

I need to store all the files in a directory to a text file with its full path.
The example below can explain:

./File1.txt
./File2.txt
./Folder1/File11.txt
./Folder1/File12.txt
./Folder1/Folder11/File111.txt
./Folder2/file21.txt
:
:

The ls -R1 command won't give the result as I desired. Please help.

Regards,
Sethu.

find . -type f | sed "s#^.#$(pwd)#"

Dear vgersh99,

Thanks a lot. It is working fine.

Is it possible to get the files ordered by Last modified date in the same pattern?

Thanks again for all.

Regards,
Sethu.

If you can use

ls -ltR yourpathandpipes

Hi Congo,

Thank you. It will be very useful for me if you could give one hardcoded example please.

Regards
Sethu.

Hi Guys,
I did something good today:

My situation:
-----------

I had 2 servers say server A and server B. Server A had got millions of files and directories. I had to keep the same ownership and group ownership in server B as in Server A. For this I did below:

1. Get to know the file ownerships in server A and put it in a file

find . -type f | sed "s#^.#$(pwd)#" | xargs ls -l | tr -s " " " " | cut -f3,4,9 -d\ > perm.conf

find . -type d | sed "s#^.#$(pwd)#" | xargs ls -ld | tr -s " " " " | cut -f3,4,9 -d\ >> perm.conf

2. copy the perm.conf on the server B under the same hierachy as in server A.

3. Then I wrote a script:

#!/bin/sh

k=`wc -l perm.conf | cut -f1 -d\ `
i=1
RECORD=""
OWNER=""
GROUP=""
FILE=""
while [ $k -ne $i ]
do
RECORD=`head -$i perm.conf | tail -1`
OWNER=`echo $RECORD | cut -f1 -d\ `
GROUP=`echo $RECORD | cut -f2 -d\ `
FILE=`echo $RECORD | cut -f3 -d\ `
chown $OWNER:$GROUP $FILE 2>> logfile
i=`expr $i + 1`
done

and I was done...

Hope this help someone...

Thanks and regards,
Pravin Goyal