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07-26-2007
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How to find whenther given value is in betwwen min and Max in unix shell scripting
Hi
I wanted to write a shell script with an if condition Example MinValue=10 MaxValue=30 logvalue = some integer value that script reads from the command line arguement I wanted to check whether log value greater than or equal to10 and less than equal to 30 and proceed with the rest of hte code only if logValue is between or equal to the MinValue and MaxVlaue If condition should work like this in unix shell scripting if(MinValue<=logValue<=MaxValue) Thanks in advance for all the help 
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07-26-2007
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Code:
#!/bin/ksh
typeset -i MinValue=10
typeset -i MaxValue=30
typeset -i LogValue
echo 'Enter log value:'
read LogValue
if [ ${LogValue} -ge ${MinValue} -a ${LogValue} -le ${MaxValue} ]; then
echo 'Found in between'
fi
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07-26-2007
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Code:
echo 20 | awk '{ if ( 20 <= $0 && $0 <= 30 ) { print "in-between" } else { print "out-of-range" } }'
Last edited by matrixmadhan; 07-26-2007 at 10:25 PM. Reason: range specification
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07-27-2007
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Thanks for the solution
It worked I am just wondering whether the ; at the end of if (if [ ];then ) is necessary or notthe reason why I was asking is it worked with out ; and with ; so just wondering is there anything that I am missing if I don't keep the ; at the end of if Is there any difference between if [ ];then fi and if [ ] then fi Thanks in advance Pinky
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07-27-2007
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The simicolon ';' is used in korn shell as a command separator.
The reason for having '; then' is to save space and have fewer lines in the shell.
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