How to find whenther given value is in betwwen min and Max in unix shell scripting

pinky · #1 (**permalink**) 07-26-2007

Hi

I wanted to write a shell script with an if condition

Example
MinValue=10
MaxValue=30
logvalue = some integer value that script reads from the command line arguement
I wanted to check whether log value greater than or equal to10 and less than equal to 30
and proceed with the rest of hte code only if logValue is between or equal to the MinValue and MaxVlaue

If condition should work like this in unix shell scripting

if(MinValue<=logValue<=MaxValue)
Thanks in advance for all the help

Shell_Life · #2 (**permalink**) 07-26-2007

Code:

#!/bin/ksh
typeset -i MinValue=10
typeset -i MaxValue=30
typeset -i LogValue
echo 'Enter log value:'
read LogValue
if [ ${LogValue} -ge ${MinValue} -a ${LogValue} -le ${MaxValue} ]; then
  echo 'Found in between'
fi

matrixmadhan · #3 (**permalink**) 07-27-2007

Code:

echo 20  | awk '{ if ( 20 <= $0 && $0 <= 30 ) { print "in-between" } else { print "out-of-range" } }'

pinky · #4 (**permalink**) 07-27-2007

Thanks for the solution
It worked
I am just wondering whether the ; at the end of if (if [ ];then ) is necessary or notthe reason why I was asking is it worked with out ; and with ; so just wondering is there anything that I am missing if I don't keep the ; at the end of if

Is there any difference between

if [ ];then

fi
and

if [ ]
then

fi

Thanks in advance
Pinky

Shell_Life · #5 (**permalink**) 07-27-2007

The simicolon ';' is used in korn shell as a command separator.

The reason for having '; then' is to save space and have fewer lines in the shell.

pinky · #6 (**permalink**) 07-27-2007

Thanks
That's really useful info I appreciate it

Pinky

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