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#1
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Is CUT the right command?
Attempting to pass in-line parameters & values to a shell script, using the CUT command to split a value where a ',' delimiter is used. The format of the passed value will be '00:00:00,00:00:00'.
If I create a file with the contents "12:34:56,12:34:56", using the command cut -d, -f1 < file I get back 12:34:56 - so far so good. However, the script below doesn't work (I've 'echoed' ${OPTARG} and the value is getting into the script OK): #!/bin/sh while getopts m: opt do case ${opt} in m) val1=`${OPTARG} | cut -d, -f1` val2=`${OPTARG} | cut -d, -f2`;; *) helpmenu;; esac done Can anyone please give me any pointers why not? Total newbie to this so I may well be missing the obvious........ |
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#2
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Kutz13,
The command 'getopts' is used to process command line arguments using the '-' (dash) format. It is not required in your specific situation. Try the following: Code:
mVal1=`echo $1 | cut -d, -f1` mVal2=`echo $1 | cut -d, -f2` |
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#3
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Sorry, maybe my terminology was wrong. What I intended to show were the arguments associated with the command line option '-m'. So that when <filename> -m 123:456,654:321 was entered I could extract into $val1 & $val2 the respective values 123:456 & 654:321.
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#4
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Quote:
Code:
m) val1=`echo ${OPTARG} | cut -d, -f1`
val2=`echo ${OPTARG} | cut -d, -f2`;;
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#5
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That's great, issue solved.
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