Grep and extract the characters after - UNIX for Dummies Questions & Answers

thumsup9 · #1 07-03-2007

Hi All,

I have lines like below in a file

A /u/ab/test1.dat
A/u/ab/test2.dat
A /u/bb/test3.dat
A/u/cc/test4.dat

I will need

/u/ab/test1.dat
/u/ab/test2.dat
/u/bb/test3.dat
/u/cc/test4.dat

Pls help

Thanks

pressy · #2 07-03-2007

Code:

root@mp-wst01 # cat testfile
A /u/ab/test1.dat
A/u/ab/test2.dat
A /u/bb/test3.dat
A/u/cc/test4.dat
root@mp-wst01 # cut -f"2" -d"A" < testfile | sed 's/ //' > newfile
root@mp-wst01 # cat newfile
/u/ab/test1.dat
/u/ab/test2.dat
/u/bb/test3.dat
/u/cc/test4.dat
root@mp-wst01 #

regards pressy

ghostdog74 · #3 07-03-2007

Code:

awk '{gsub(/^A\ */,"")}{print}' file

lorcan · #4 07-03-2007

I hope that you do not want the first character in your file, so below command would help you

Code:

cut -c2- file > newfile

anbu23 · #5 07-03-2007

Code:

sed "s/^A *//" filename

matrixmadhan · #6 07-04-2007

Code:

sed 's/^. *//' filename

Ygor · #7 07-04-2007

Code:

sed 's!^[^/]*!!' filename

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