hey guys this is my first post here, heard a lot about these forums. Iam urgently in need of a command which would help me accomplish the following , for example a file has these contents:

211 61 2007-06-26 13:47:32
211 61 2007-06-26 09:53:43
211 61 2007-06-26 15:25:14
211 61 2007-06-26 04:32:11
211 61 2007-06-26 21:12:36
211 61 2007-06-26 02:11:27



now , i need to EGREP a pattern which would give me the following output:

211 61 2007-06-26 13
211 61 2007-06-26 09

basically, all lines are same.. what i need to EGREP is in each line "the range of grepping would be from 211 to hours i.e 00,12,09 etc.

egrep -e "211 2007-06-26 $$" ??

date is fine ,everything is same..i just need to know the command which would grep me the contents uptil the 2 digits of HOURS.


urgent reply needed!! thanks!

Can you please explain what do you mean by 2 digits of HOURS?

hello !

by two digits i mean


13:47:56
14:11:21:


basically 13 and 14 are the 2 digits

i need an output which would begin from 211 and end on the 2 digits of the hours , e.g. following is what i desire as a result:

211 61 2007-06-26 13
211 61 2007-06-26 09
211 61 2007-06-26 01
211 61 2007-06-26 00
211 61 2007-06-26 12
211 61 2007-06-26 06

so u see it is showing 2 digits of hours, no minutes or seconds after that.

basically this is a 300 mb text file which is showing 211 61 transactions with date and time

i need to know the command so it can show uptil HOURS only (no minutes or seconds) so i can see which transaction is made at what hour (no minutes or seconds)

wow thanks a lot anbu23!!!!!

now iam facing another problem

ok for example i need to grep only the transaction of 14th hour i will do this:

cut -d':' -f1 filename|grep "14"

it will show:
211 61 2007-06-26 14
211 61 2007-06-26 14
211 61 2007-06-26 14
211 61 2007-06-26 14


now what if i need to see the files which are of 00 hour??

cut -d':' -f1 filename|grep "00"

if i do this it will show all the files because 2007 also has two zeros.