Hi everyone:

I'm trying to make a CRON job that will execute Fridays at 7am. I have the following:

* 7 * * 5 [command]

I've been studying up on CRON and I know to have this in a file and then "crontab filename.txt" to add it to the CRON job list.

The CRON part I believe I understand, but I would like this job to execute all .ksh scripts in a specific folder (/usr/scripts). I'm not sure of the UNIX command to do so.

Could someone please help me with this? Thanks for any help.

Create a script like:

#!/bin/ksh
cd /usr/scripts
list=`ls *.ksh`
for script in $list
do
$script
done

Don't forget that the path in cron is not likely to be the same as your login shell.

You could write a script like this:

Thank you all for the help. Not all of the files in the script directory are scripts, so the first script would probably suit me better.

Please forgive my "newbie-ness", but let me just double check things:

1.) I have a text file scriptCron.txt with this in it:

* 7 * * 5 /home/oracle/executeScripts.sh

2.) I have the executeScripts.sh file chmod'd to 777 and containing this:

#!/bin/ksh
cd /home/oracle/scripts
list=`ls *.ksh`
for script in $list
do
$script
done

3.) All I need to do is "crontab scriptCron.txt" and then it should be added to the crontab list.

And that should be it.

Does the user have to be logged in for the CRON jobs to run or will it run automatically?

Thanks again for the help.

No the user does not have to be logged in.
Also be aware that stdin and stdout do not exist, so if any of your scripts expect input that input should be pre-set in a file, and any output should be redirected to a file.

Annorax,

- A user does not have to be logged in for the cron to run.

- You do not need to have a *.txt file and pass it to crontab.
Run:
=> crontab -e

And you can edit the crontab file.

An easy way would be:

=> crontab -l
* 7 * * 5 /home/annorax/cronscript



=> vi /home/annorax/cronscript

/usr/scripts/script_1
/usr/scripts/script_2
/usr/scripts/script_3
...
...
...
/usr/scripts/script_n