hi gurus!
i realize that my question shows my stupidness, but i need your help!

i have:
s_date=`date +%m-%d-%Y_%I%p`
variable and i need the same, but minus one hour..
what i made:
s_date=time(`date +%m-%d-%Y_%I%p`) - 3600

but i'm getting:
daily_exports.sh: line 20: syntax error near unexpected token `('
daily_exports.sh: line 20: `new_date=time()-3600'

also i did:
new_date=time()-3600
s_date=strftime(`date +%m-%d-%Y_%I%p`, new_date);

etc.. nothing works,
please, help!

Thank you beforehand,
Maria.

Maria,
Date calculation can be very involved as you have to consider
end of month, end of year, leap year, etc.
Here is a thread that can help you in this issue:
http://www.unix.com/answers-to-frequ...rithmetic.html

Oh, thank you for your help!
this is great source!

Thanks,
Maria.

still fighting. I'll really appreciate any help.
thank you,
M.

cool, i found!
date -d "-1 hour"
works pefectly,
thank you!