Run a program for every file with a given extension

Phobos33 · #1 (**permalink**) 06-01-2007

Hey all

I have written a python program that takes as input the name of a data file with the extension .lc I would like to write a shell script that finds all of the .lc files in a set of branching directories and runs the program.

Any help?

blowtorch · #2 (**permalink**) 06-01-2007

Use the 'find' command for that. Run the output of that command through a for or a while loop that will run your python command for each file that is found.

Phobos33 · #3 (**permalink**) 06-01-2007

err.... anything more specific than that... im new to all this.
so i use find to create an array that stores all of the files i will need and then i run my program for each on inside a for loop??

Phobos33 · #4 (**permalink**) 06-01-2007

Hey
When you say pipe it into python, how do i pipe it in as one of the arguments

find /path -type f -name "*.lc" -print | python tester.py ########

I want to put the output where ######## is.

Thanks

ghostdog74 · #5 (**permalink**) 06-01-2007

here's a snippet. Use the sys.stdin.readlines() method in your python script

Code:

import sys
print sys.stdin.readlines()

then from shell:

Code:

# find /path-type f -name "*.lc" -print | ./test1.py
['/path/user/test.lc\n', '/path/test/test1.lc\n']

ghostdog74 · #6 (**permalink**) 06-01-2007

you can find those files in Python itself. this way, you don't have to maintain an extra shell script.
some of the modules in Python you can use to find files are: os.walk(), glob , os.path.splitext() etc...

here's a snippet:

Code:

#!/usr/bin/python
import os
for root,dir,files in os.walk("/home"):
    for file in files:
        if file[-3:]==".lc":
            fullpath=os.path.join(root,file)
            do_something(fullpath)

however, if you want to use the shell to find those files, you can use "find" command

Code:

find /path -type f -name "*.lc" -print > file # or pipe to you python program

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