Help in renaming file !!!

kumarsaravana_s · #1 (**permalink**) 05-02-2007

Hi All,

I want to rename a file inside a script which has a date portion appended at the start of the file name.

The script i wrote works fine when the file comes on a day to day basis but sometimes it comes late too.

#!/usr/bin/ksh

cd /space/file/source

dt=$(date "date "+%m%d%Y")
mv $dt_xxx_yyy_aaa_bbb.txt xxx_yyy_aaa_bbb_$dt.txt

input:
04302007_xxx_yyy_aaa_bbb.txt

output should be like
xxx_yyy_aaa_bbb_04302007.txt.

I know sed or awk can do this by extracting the numeric part and then appending it to the end of file name.But me totally new to such things.Can someone help me extracting the date portion and then adding it just before the extension?

Thanks,
Kumar

ghostdog74 · #2 (**permalink**) 05-02-2007

just one of the many ways:

Code:

newfile=$( echo 04302007_xxx_yyy_aaa_bbb.txt  |awk 'BEGIN { FS = "."}
						 {	
							n = split($1,s1,"_")
							for(i=2;i<=n;i++) printf "%s_",s1[i]
							printf "%s.%s\n",s1[1] , $2
						 }' )
echo $newfile

output:

Code:

# ./test.sh
xxx_yyy_aaa_bbb_04302007.txt

anbu23 · #3 (**permalink**) 05-02-2007

Code:

$ nm=04302007_xxx_yyy_aaa_bbb.txt
$ flnm=${nm#*_}
$ dt=${nm%%_*}
$ ext=${nm##*.}
$ echo ${flnm%.*}"_"${dt%?}"."${ext}
xxx_yyy_aaa_bbb_0430200.txt

kumarsaravana_s · #4 (**permalink**) 05-02-2007

Quote:

Originally Posted by anbu23

Code:

$ nm=04302007_xxx_yyy_aaa_bbb.txt
$ flnm=${nm#*_}
$ dt=${nm%%_*}
$ ext=${nm##*.}
$ echo ${flnm%.*}"_"${dt%?}"."${ext}
xxx_yyy_aaa_bbb_0430200.txt

Hi Anbu,

Thanks for your help.Could you please explain the symbols #,% you had used in the script.

Thanks again,
Kumar

ennstate · #5 (**permalink**) 05-02-2007

From the man pages,

Code:

       ${name#pattern}, ${name##pattern}
              If pattern matches the beginning of the value of parameter name,
              the matched text is deleted from the result of substitution.   A
              single  #  results in the shortest match, two #’s results in the
              longest match.

       ${name%pattern}, ${name%%pattern}
              Like ${..#..} substitution, but it deletes from the end  of  the
              value.

Thanks
Nagarajan Ganesan.

kumarsaravana_s · #6 (**permalink**) 05-02-2007

Quote:

Originally Posted by ennstate

From the man pages,

Code:

       ${name#pattern}, ${name##pattern}
              If pattern matches the beginning of the value of parameter name,
              the matched text is deleted from the result of substitution.   A
              single  #  results in the shortest match, two #’s results in the
              longest match.

       ${name%pattern}, ${name%%pattern}
              Like ${..#..} substitution, but it deletes from the end  of  the
              value.

Thanks
Nagarajan Ganesan.

Thanks Nagaraj.

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