|
|
|
|||||||
| Home | Forums | Register | Rules & FAQ | Members List | Arcade | Search | Today's Posts | Mark Forums Read |
| UNIX for Dummies Questions & Answers If you're not sure where to post a UNIX or Linux question, post it here. All UNIX and Linux newbies welcome !! |
Other UNIX.COM Threads You Might Find Helpful
|
||||
| Thread | Thread Starter | Forum | Replies | Last Post |
| print line whatever line i want in a file... there any way | kittusri9 | Shell Programming and Scripting | 1 | 05-15-2008 09:37 AM |
| awk print the next line on the current line | ajp7701 | Shell Programming and Scripting | 4 | 04-17-2008 01:50 PM |
| How to print a value in the variable using awk ? | jisha | Shell Programming and Scripting | 1 | 01-14-2008 03:45 AM |
| Print file line by line | handak9 | Shell Programming and Scripting | 2 | 10-20-2005 05:44 AM |
| print variable in awk | kazanoova2 | Shell Programming and Scripting | 8 | 05-17-2004 03:30 PM |
 |
|
|
Submit Tools | LinkBack | Thread Tools | Search this Thread | Display Modes |
04-24-2007
|
|||
|
|||
|
use variable for sed print line
I'm using the sed command to pull a line from a file and place it into another file:
sed -n '1p' students >tmp this pulls the first line, I want to change the 1 to a variable which will be a counter to go through the rest of the lines but can't get it. I've tried: sed -n '$cp students >tmp sed -n $cp students >tmp neither work. Any ideas? Thanks! 
|
| Forum Sponsor | ||
|
|
Linear Mode
