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  #1 (permalink)  
Old 04-20-2007
arun_st arun_st is offline
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Join Date: Mar 2007
Posts: 4
IF THEN ELIF question in BOURNE SHELL

Hi,

I get an error when executing this sample script.

#!bin/sh
if [ $1 = ];
then
echo "you need to enter the release as the first parameter"
elif [ $1 = "ALL" ];
then
echo "HI how are you ABC"
echo "Hi how are you XYZ"
echo " hi how are you all"
else
echo "using the $1 as input parameter"
fi

i get the following error.
[: arun.sh 5: FSUM6807 expression syntax error

the script requires a parameter to be passed.. If no parameter is passed the script works fine and it displays the right message. and if the parameter is ALL then also it works fine...i get the above error only if the parameter is other than null or ALL.. how to resolve this...looks like there is a problem with the else statement.
  #2 (permalink)  
Old 04-20-2007
anbu23 anbu23 is offline Forum Advisor  
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Join Date: Mar 2006
Location: Bangalore,India
Posts: 1,398
Change
Code:
if [ $1 = ];
to
Code:
if [ -z $1 ];
  #3 (permalink)  
Old 04-20-2007
johnf johnf is offline
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Join Date: May 2006
Location: England
Posts: 284
Quote:
Originally Posted by anbu23
Change
Code:
if [ $1 = ];
to
Code:
if [ -z $1 ];
if [ $1 = "" ];
  #4 (permalink)  
Old 04-20-2007
reborg's Avatar
reborg reborg is offline Forum Staff  
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Join Date: Mar 2005
Location: Ireland
Posts: 4,190
Don't forget to quote the variable with -z, otherwise an unset variable will break the script.

Code:
if [ -z "$1" ];
  #5 (permalink)  
Old 04-20-2007
arun_st arun_st is offline
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Posts: 4
It worked

Hi

I tried ur suggetion and it worked. Thanks a lot
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