IF THEN ELIF question in BOURNE SHELL

arun_st · #1 (**permalink**) 04-20-2007

Hi,

I get an error when executing this sample script.

#!bin/sh
if [ $1 = ];
then
echo "you need to enter the release as the first parameter"
elif [ $1 = "ALL" ];
then
echo "HI how are you ABC"
echo "Hi how are you XYZ"
echo " hi how are you all"
else
echo "using the $1 as input parameter"
fi

i get the following error.
[: arun.sh 5: FSUM6807 expression syntax error

the script requires a parameter to be passed.. If no parameter is passed the script works fine and it displays the right message. and if the parameter is ALL then also it works fine...i get the above error only if the parameter is other than null or ALL.. how to resolve this...looks like there is a problem with the else statement.

anbu23 · #2 (**permalink**) 04-20-2007

Change

Code:

if [ $1 = ];

to

Code:

if [ -z $1 ];

johnf · #3 (**permalink**) 04-20-2007

Quote:

Originally Posted by anbu23

Change

Code:

if [ $1 = ];

to

Code:

if [ -z $1 ];

if [ $1 = "" ];

reborg · #4 (**permalink**) 04-20-2007

Don't forget to quote the variable with -z, otherwise an unset variable will break the script.

Code:

if [ -z "$1" ];

arun_st · #5 (**permalink**) 04-20-2007

Hi

I tried ur suggetion and it worked. Thanks a lot

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