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04-12-2007
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grep command help
Hello, im trying to grep the first 3 lines(starting with ERROR) from an output report and put it in a separate file... any help would be appreciated. Below is the message contained in the report
ERROR >Invalid basic data (CMOFCT-5070) Cusip: 05950XAL0 CMO#508039 Tra# 11 rec# 175 Firts Int Pay Date: 1061110 Bond type flag: V Floater type Flag: 3 Floater Reset Start Date: 0 Floater Reset Frequency: 0 thanks |
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04-12-2007
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Give this a try,
grep -n "^ERROR" /tmp/err | head -3 INPUT: HTML Code:
cat /tmp/err ERROR:Quota exceeded MISC DEBUG WARNING ERROR FAULT ERROR DEBUG ERROR ERROR TYPE 1 SEVERE ERROR ERROR EXITING HTML Code:
1:ERROR:Quota exceeded 5:ERROR 8:ERROR TYPE Nagarajan Ganesan. |
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04-12-2007
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Hi thanks for the help.. unfortunately it didnt work.. maybe im explainin it wrong... i am running a file and it spits out an output file r.(filename) and in that output file it has several messages... im lookin to take out the first 3 lines of messages that start with ERROR and put it into another file named geek... thanks
Last edited by geekeezoid; 04-12-2007 at 04:47 PM.. |
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04-12-2007
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geekeezoid,
See if this would work for you: sed -n '/ERROR/,$p' input_file | head -3 |
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04-12-2007
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Hi, thanks... i think it took out the first 3 lines of the first ERROR message.. but there are several ERROR messages in the r. output file... any way to take the first 3 lines of all the ERROR messages? thanks
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04-12-2007
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Geekeezoid,
Try this one: Code:
mTotal=0
while read EachLine
do
if [[ $mTotal -gt 0 ]]; then
echo $EachLine
mTotal=$mTotal+1
if [[ $mTotal -gt 2 ]]; then
mTotal=0
fi
else
mCnt=`echo $EachLine | egrep -c "ERROR"`
if [[ $mCnt -ne 0 ]]; then
echo $EachLine
mTotal=1
fi
fi
done < input_error_file
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04-12-2007
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Code:
awk '/^ERROR/ { end = NR+3 } NR < end { print }' report > new_file
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