Unix find command to print directory and search string

princein · #1 (**permalink**) 03-06-2007

Hi

i need to print pathname in which the string present using 'find' command

sample output like this

Pathname String to be searched
---------- --------------------
/usr/test/myfile get
/opt/test/somefile get

Thanks in advance

ranj@chn · #2 (**permalink**) 03-06-2007

Did you want to list the file that had the word 'get'. Is that the string you are referring to? Se if this works for you -

Code:

find /dir/from/where/you/want/to/search -type f -exec grep -l 'get' {} \; 2>/dev/null

dennis.jacob · #3 (**permalink**) 03-06-2007

If you want to get the details of the file containing string 'string', you this

grep -ir 'string' /dir/from/where/you/want/to/search

arunkumar_mca · #4 (**permalink**) 03-06-2007

Hope u can use find with Xargs .. Will be the simple ways !!!!!!!

andryk · #5 (**permalink**) 03-06-2007

Quote:

Originally Posted by ranj@chn

Did you want to list the file that had the word 'get'. Is that the string you are referring to? Se if this works for you -

Code:

find /dir/from/where/you/want/to/search -type f -exec grep -l 'get' {} \; 2>/dev/null

Thanks dude, its been ages that i've searched for that kind of command!

Knowing not the minus l option of grep, I used to

Code:

find /dir/from/where/you/want/to/search -type f -exec cmd.sh 'get' {} \;

where cmd.sh is

Code:

grep $1 $2 2>/dev/null
[ $? -eq 0 ] && echo $2

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