regular expressions - UNIX for Dummies Questions & Answers

ragha81 · #1 (**permalink**) 03-05-2007

Hi Gurus,

I need help with regular expressions. I want to create a regular expression which will take only alpha-numeric characters for 7 characters long and will throw out an error if longer than that.

i tried various combinations but couldn't get it, please help me how to get it guys.

Thanks

zazzybob · #2 (**permalink**) 03-05-2007

Code:

$ echo "123abc7" | grep '^[A-Za-z0-9]\{0,7\}$' || echo ERROR
123abc7
$ echo "123abc78" | grep '^[A-Za-z0-9]\{0,7\}$' || echo ERROR
ERROR

If you want exactly 7 characters, just change the regex to

Code:

'^[A-Za-z0-9]\{7\}$'

Cheers
ZB

ragha81 · #3 (**permalink**) 03-05-2007

thanks for ur reply, it worked..

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