Variables - UNIX for Dummies Questions & Answers

bobo · #1 01-18-2007

data1 contain:
100;1
390;3
1;2
144;6

data2 contain:

100;1
300;4
1;2
130;4
144;6
390;3
.....
....
.......... and so on...

I have this program:

#!/usr/bin/ksh
cat data1 | while read line
do
grep "$line" data2 > ouput$line
done

I get the followin files:

output100;1
output390;3
output1;2
output144;6

I can't even open these file since its format with ";" in the middle of the file.

Questions:

Are there ways that I can make each rows of data1 into 2 seperate variables?
What I need to do to get the following results?

output100for1
output390for3
output1for2
output144for6

I can't think of ways to do it. Please advise

anbu23 · #2 01-18-2007

Code:

IFS=";"
while read no1 no2
do
grep "${no1};${no2}" data2 > Output${no1}for${no2}
done < data1

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